The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF).

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Rewrite Strategy: FULL

(1) DecreasingLoopProof (EQUIVALENT transformation)

The following loop(s) give(s) rise to the lower bound Ω(n¹):
The rewrite sequence
+(s(N), s(M)) →⁺ s(s(+(N, M)))
gives rise to a decreasing loop by considering the right hand sides subterm at position [0,0].
The pumping substitution is [N / s(N), M / s(M)].
The result substitution is [ ].

(2) BOUNDS(n^1, INF)